Recent content by llatosz

Sorry for two questions in a row, this one we have been stumped on for the entire day We're getting "fatal error. detector no. 1 of tally 5 is not in any cell.", What could be causing this? In the manual and all examples we've seen, nobody has parameters specifying cell location for the...

This worked very well and was actually what my coworker suggested too! Thank you very much

I'm modelling a scenario for the research that I'm working on, and I got the cells and surfaces all mapped out for the environment finally, but now I'm totally stuck on creating a source. I'd like a point source of Californium-252, but after hours of looking, I don't see any out of the 1000...

I used to be like this back in my calc 1 and 2 days. I would study up on theorems that we didn't cover out of pure bright eye-ed interest, and I'd even wanted to discover and create my own theorem. But, unfortunately, that has all dwindled down and now I've been entirely jaded when it comes to...

Same. I studied every day for about the first two weeks of junior year in high school/college dual enrollment. Never did that again. The ones who can actually enjoy studying for hours on end are beyond my understanding. Also very lucky lol

Oh wow, youre right, that's pretty neat! Oh okay, this totally makes sense now! And yes, I am getting the same result as you for 3 wins too! Makes sense, thank you! :D Now I can formulate some numbers for my friend's loot drop gambling in a video game we play! There's an item he wants with a...

Ah okay! Thanks! So p is probability of success and q is probability of fail from what I infer. So, going forward "1 win" just means any 1 win, so, P(1 win) = (0.01) * (0.99)99 * 100combos = 0.3697 = 36.97% But then P(2 wins) = (0.01)2 * (0.99)98 * (99*99)combos = 0.366 = 36.6% ... which...

Yes that is kinda what I'm asking lol. I'm aware that for 1 success there are 100 different combinations, and that for 2 successes there are like 998 or 999 combinations. So the chance of success on throw 1 is 1%, and failure on every following throw is .99^99 = 36.97%, so the chance of 1...

What is the probability of no success? 1 success? 2 successes? No success: 0.99^100 = 36.6% chance? 1 success: (0.99^99) + 0.01 = 37.97% chance? or (0.99^99) * (0.01)^1 = 0.369% chance ? You would think it would be fairly likely 2 successes: ? -Depends on formula for 1 success Can...

Ohhh I see the difference in our calculations! But I did say "But, this many school hours + work + sleep, would make enjoying your life almost impossible." in my post. I had to work around 35-40 hours per week to pay for rent, gas, and food and stuff :/ I always forget for some people being a...

Agreed. And to add, I think 60 working hours a week is too much for anyone to enjoy their life at any stage; high school, college, career. But you also wrote: "My rule of thumb for success in college is that students should spend 2-3 hours outside of class for each class hour per week. A 15...

I'm going to agree on all of the reasons you made that work ethic is a key to success, but I'm also going to have to completely disagree for the following reasons: "Success" is a terribly relative term and personally, your son doesn't sound very successful. (while objectively I am sure he is...

Oh, i think my diagram is just wrong then. I already wired up two light strips in parallel with each other to one of the switches on the switch panel and they've been working great for months. So just ignore the switch panel So the new diagram would be like this. If the left works (by magic)...

Oh okay. So anyway, I think my diagram is good. Is there anything that you may notice that I am overlooking that could raise concern to safety or sound quality

Yikes, that diagram is confusing! I take it Q1 is a relay-type of switch, D1 is a diode to make current go to the lights only on one direction of the AC current? No clue what the capacitors would be for o_O Sure! This is what I mean