Recent content by Lobber

I think I might have fixed my problem as ay=Fgy=0 so that changes things. Also it's an inclined plane question.

D=1.83M T=1.06S A=3.257m/s/s angle/theta is 54 degrees Vi=0 M=0.5kg Friction force? Normal force? Mu? Formula#1 (didn't work...) Ff: (cos theta A)*M=Max=Fx Fx=Ffx-Fgx Fgx=(sin theta)Mg. Fn: Ma(sin theta) = May May=Fy=Fny-Fgy Fgy=M*(cos theta)g Ff/Fn=mu Formula2 Fx=Max ax=a(cos theta) Fy=May...

Homework Statement What is the formula for: Fn, Ff, and mu when you have a object sliding down a ramp. Variable know are D, T, A, Vi, and the angle of the ramp above the horrizon. The Attempt at a Solution I've tried a few that ended up being quite long and all wrong...

What I need it a formula that relates Fnety=MAy and Fnetx=MAx to related normal force and friction force and how the formula is derived.

I don't know don't have the answers for it... the answer I did get for your formula was mu=.811

Well the main purpose of the assignment to to get the coefficient but we also need the Ff and Fn and how we got to all 3 in the most basic of steps... Sign and I thought I finally had my formula...

What is the coefficient of friction for a metal mass sliding down a wooden slope? Mass=0.50kg Slope distance=1.83m Angle=54 Degrees Time=1.06 s Vi=0m/s g=9.81m/s/s For this question we had to write out a formula and find mu. I first found acceleration to be 3.257m/s/s, Friction force to be...