- #1
Lobber
- 7
- 0
What is the coefficient of friction for a metal mass sliding down a wooden slope?
Mass=0.50kg
Slope distance=1.83m
Angle=54 Degrees
Time=1.06 s
Vi=0m/s
g=9.81m/s/s
For this question we had to write out a formula and find mu.
I first found acceleration to be 3.257m/s/s, Friction force to be 4.9255N, Natural force to be 4.201N, and mu to be 1.1725.
My formula was:
D-Vi*T/0.5T^2=A
Fnetx=Fnetx
Fx=Max
Ax=(cos theta)A
Fg=mg
Fgx=mg(sin theta)
Fx=Ff-Fgx
Fx+Fgx=Ffx
Fnety=Fnety
Fy=MAy
Ay=(Sin theta)A
Fg=Mg
Fgy=Mg(cos theta)
Fy=Fny-Fgy
Fy+Fgy=Fn
Ff=mu Fn
Ff/Fn=mu
I know it have a lot of unnecessary steps in there but it is to show where my forces are coming from and what they are (my teacher is a step Nazi and everything must be written down no matter how useless and repetitive...) Now my question is whether or not that formula is correct, if my answers are correct, and if/how the formula can be shortened.
Mass=0.50kg
Slope distance=1.83m
Angle=54 Degrees
Time=1.06 s
Vi=0m/s
g=9.81m/s/s
For this question we had to write out a formula and find mu.
I first found acceleration to be 3.257m/s/s, Friction force to be 4.9255N, Natural force to be 4.201N, and mu to be 1.1725.
My formula was:
D-Vi*T/0.5T^2=A
Fnetx=Fnetx
Fx=Max
Ax=(cos theta)A
Fg=mg
Fgx=mg(sin theta)
Fx=Ff-Fgx
Fx+Fgx=Ffx
Fnety=Fnety
Fy=MAy
Ay=(Sin theta)A
Fg=Mg
Fgy=Mg(cos theta)
Fy=Fny-Fgy
Fy+Fgy=Fn
Ff=mu Fn
Ff/Fn=mu
I know it have a lot of unnecessary steps in there but it is to show where my forces are coming from and what they are (my teacher is a step Nazi and everything must be written down no matter how useless and repetitive...) Now my question is whether or not that formula is correct, if my answers are correct, and if/how the formula can be shortened.