Recent content by lola1227

So, would we use the parallel/perpendicular or the vertical/horizontal and would we have two unknowns and plug one unknown into the other to solve them?

We’re supposed to do it using vector components (horizontal/vertical) or paralllel/perpendicular but I’m not sure what to do or how to start it.

I meant to write COs theta which is the x and yeah I réalisés now I can’t use 3 for V1’

This is all that was given to us - and the drawing was given to us like this with these angles and everything

Parallel: M1V1+M2v2=M1V1’+M2V2’ (0.5)(3)+0=(0.5)(cos60)(3)+V2’Cos(x)(0.5) V2’cos(x)= Perpendicular: M1V1+M2v2=M1V1’+M2V2’ 0=(0.5)(0.3)(sin60)+V2’sin(x)(0.5) V2’sin(x)= And the divide 2 by 1 Which is tan(x)=2/1 And then plug then back into solve, but I don’t think we do it like this because...

Thank you so much for your help!

That's Okay! So the relation is that you have more of that number every time? So like at first you have a 1/4 wavelength which is how you got 400 frequency then to get the 3/4 frequency you would multiply by 3 so you would get 1200Hz and then for 5/4 multiply by 5 so you would get 2000Hz...

Just to see if I understand properly, I would use a number such as 343, or 331 as my speed of sound and then I would divide the 400 by this number? After that I would use L=1/4(lambda) and multiply the number that I got previously by the different frecations?

Hi, we were just given this formula and another formula that we have is that the speed of sound is V=331+0.59T this is why i was confused with the question because there was not enough information given the fractions tell me that the frequency will be divided by 1/4?

So, my thinking was that we use the formula V=f(lambda) and substitute the f so, V = 440(lambda) but then i don't have another number to cancel or rearrange by. And since closed air columns have the fractions of 1/4, 3/4, and 1 1/4 (5/4), we could divide by those?

Thank you very much for your help!

9.8x=1.62x+25 9.8x-1.62x=25 8.18x=25 x=3.056?? so would the mass be 3.056kg?

i see. would the equation be m(9.8)=m(1.62)+25?

so fe+25=fm