Recent content by Lolagoeslala

i am getting 4.60

i do not know how to find the constant angular acceleration

ωf = 2ωavg = 2(2π)/30 . Angular acceleration, α = (ωf-0)/30 . That's 1/4 of the former answer.

i am abit confused

1.4 , 2.99 , 4.39 , 4.60 , and 5.78

but the answer does not match up with the answers possible.

so that's the answer i do not need to worry about the orientation?

c^2 = (17.52 m/s^2) ^2 + (5.58 m/s^2 )^2 c = 18.38 m/s^2

i am bit confused i have not worked with tangential component before

a = 17.52 m/s^2[W] + 5.58 m/s^2 [S] like this?

157 m x 2 / 7.5 s =v2 41.866 m/s = v2 a = v^2 / R a = 41.866 m/s^2 / 100m a = 17.52 m/s^2

a = 5.58 radm/m^s2 v at the 1/4 point. You can do that by solving for the time it takes him to go to the 1/4 point d = 200 m C = 200 m x 3.14 C = 628 m D = 1/4 628 m = 157 m 157 m = 1/2 (5.58 radm/m^s2)(t)^2 t = 7.5 s 157 m x 2 / 7.5 s =v2 41.866 m/s = v2 a = 41.866 m/s /100m...

like this? π/56.25 rad/s^2 x 100 m = a 5.58 radm/s^2 = a

a= π/56.25 rad/s^2

π/7.5 rad/s = at π = a