Recent content by lolbob07

Work = F x D F=mg F=110 x 9.8 F=1078 N But how do we find the distance?

Homework Statement In 1979 the human powered Gossamer Albatross flew across the English Channel. The pedalling pilot averaged 190 W over the distance. If the pilot's power was used to lift a 110 kg mass, to what height would he lift the mass in a time of 25 s? Homework Equations P = W/T...

Umm yeah Sorry. I didn't realize they were 3 columns that we could fill in. Because with my second question I asked on another thread I realized. :/

lol. I thought you noticed that before. Sorry! It was just a numbers error :/ Thanks for the help.

No, sorry I can't understand how to identify the input and output. Is the final output energy the potential energy at the top?

Not sure if this is correct. But, is 176400 the input and 383600 is the output (560000 - 176400)? Does the 383600 count as wasted energy?

Hahahha! Well thanks! I think that solves it :) Just changed it

No it does not, which is the reason I asked. Is it referring to how much energy the person uses per metre of walking?

Just want to make sure If I have solved this question correctly. Homework Statement A 75 kg person walks to the top of a 240 m high hill expending 5.6 x 10^5 J of energy/ a. What was the potential energy of the person at the top of the hill? b. What is the efficiency of the person in walking...

We have not learned equations of motion. I have no clue about them.

Thanks. I don't understand why our teacher gave us this question when we hadn't learned the work energy theorem... Anyways thanks.

So, If I assume It is constant. The answer = 4500 N x .23 m = 1035 J?

Hi everyone. I'm quite troubled with this physics question. A .035 kg bullet is fired from a .23 m barrel. The bullet experiences a force of 4500 N while in the gun barrel. What is the kinetic energy of the bullet as it leaves the gun barrel? I don't understand how to figure out the...