Recent content by longnh

I might see it now. I used to think that the pivot was that G point, but I was wrong. If the truck was rotated, the pivot would be the front axle. At the front axle point: w.d = F2.2d ⇔ F2 = w/2 Thank you!

I'm talking about the mass center of the unloaded truck.

Yes, haruspex, because the truck didn't rotate, sum of counterclockwise moments (front wheels) equals to clockwise moment (at rear wheels). So I have M'1 = M'2 written above. If I choose an axis with positive direction from left to right, then ∑M = 0 ⇔ (W'/2).d - w.2d - (W/2).d, which is the...

Thank you guys for tipping. In a lazy way, the answer should be (a). w/2 but I cannot find a solution to that result. Consider G stays unchanged. At early state: M1=M2 <=> F1.d = F2.d <=> W1 = W2 = W/2 When that block is loaded, we have M'1=M'2 <=> F1.d + F.2d = F'2.d <=> (W/2).d + w.2d =...

Homework Statement A forklift truck of weight W has dimensions shown in the figure below. Its centre of gravity G is mid-way between the front and the rear axles. When a uniform block of weight w (w < W) is placed on the front forks as shown, how the load on the rear axle will change...