Recent content by louie3006

the kirchhoffs rule as a whole. I tried solving this problem in the following way : R= 1/32 + 1/20 = 0.083 ohms I= V/R = 30/0.083= 360 amps which I know is wrong so what can I do, I spent the last hour watching a professor from MIt working a similar problem yet he did not show it with...

i'm staring at the same problem and yet don't get how to solve it ? can anyone offer me any help?! I might have this problem on my final exam this coming monday may 10th , 2010. help please

how can i tell if a molecule is dextorotory or levorotory by looking at the 3-d presentation? any thoughts!

alright, so my question is: how can anyone find / search for a research opportunity to get involved. as of right now I'm an undergrad student and I hear things from other students like getting internships, research programs etc and I honestly feel lost when they start talking so is there like a...

well, what happens is that the 2.00Kg hits the 1.50Kg mass which cause it to swing and then keeps moving straight forward till it reaches 30 degree incline and travels a distance of 1.125m I posted a link that has the diagram up above if you like to look at it.

PE=mgh= (2.00kg)(9.80m/s^2)(1.25m) =24.5J

so here is what i tried, but I don't know if I'm right i just followed an example in the book that is somehow similar to this problem. m1=2.00kg m2= 1.50kg height to which the block and pendulum swings hf=1.25 (m1+m2)Vf= m1Vο + 0 Vο = (m1+m2/m1)Vf Vο= (m1+m2/m1) √ghf Vο = (2.00kg + 1.50kg /...

I don't know where to start?

Homework Statement a simple pendulum consist of 1.50Kg mass connect to a cord without any mass or friction. initially the pendulum is vertically positioned when a 2.00Kg mass collides with it, causeing the pendulum to displace vertically upward 1.25m. after the collision, the 2.00Kg mass...

thank you

we need to find out if the function is increasing or decreasing by using the first derivative test and then setting it equal to zero, but i don't know how to get the 1st derivative of this thing ? any thoughts on that ?

Homework Statement y= x √6-x^2 Homework Equations The Attempt at a Solution

Homework Statement find the slope of the tangent line whose g(x)=x^2-4 at point (1,-3) Homework Equations lim f(x+Δχ) -F(c)/ (Δχ) The Attempt at a Solution g(x)= x^2-4 G(1+Δχ)= (1+Δχ)^2-4 ==> Δχ^2+2Δχ-3 lim (Δχ^2+2Δχ-3) - (-3)/(Δχ) = 0 but in the book the answer is 2 so what...

f(6) = 1/ (6-6) = 1/0 this function is discontinuous, right ?

when x = -6, that would make f(x) = 1/x-6 discontinuous right?