Hi.
I have 3D printer with a heated bed, made of a 400x300 mm aluminium, that is 4mm thick. The surrounding air temperature is about 10°C. When printing with different materials, it is required to keep the bed at different temperatures. What I experience is that the driver which controlls...
One thing is sure. Air resistance increase rapidly with velocity. It is the dominating factor as velocity pass 7'ish mph. So any hope of gaining back som of the energy on a horizontal ride is little. However, when climbing a hill, and not take the advantage of a "free ride" downhill will...
It is really 42Ah, forty two :-)
One LiFePo at 20Ah on the luggage carrier behind the seat and a stack of LiPos at 22Ah in between the frame. Both with separate BMS. I have approx 130km range if I sweat a little.
The total weight is less than 30kg. The 20Ah battery is about 7kg. The Lipo is much...
The parts I ordered for this experiment did cost almost nothing. I do this for the cause of the experiment and do not have high hopes. Just wanted some input from skilled people to prevent possible hazards :-). I will test my bike with and without regen. on my way to work - which is 29km one...
Thanks for the replies folks! My major concern was wether to use a switch or not to prevent possible shortcircuit or maybe a damaging feedback loop - depending on how you see it. The converter will feed the ESC input with 45V which possibly will conflict with the battery output. That means...
Hi there :-)
I got that crazy idea to make regeneration of electricity on my e-bike when the bike runs downhill, by using its motor as a generator when the throttle is off.
My e-bike is custom made by myself. The motor is located in the front wheel hub, and it provides 7 Volt 3-phase voltage...
Using water in a 1x1x1m tank. Initial potential energy is:
Ep=m×A×(h/2)×g
1000×1×0.5×9.81=4902J
When both tanks, 1 and 2, is 1/2 full:
Ep1= Ep2=
500×1×0.25×9.81=1226.25J
Eptot=Ep1+Ep2=2452.5J
When both tanks are empty the difference is:
2xEptot=4902J
Makes this sense? Seems logical to me...
Ok. I misphrased that reference level. The ground reference does not longer apply when the reference now is on the surface of the fluid inside the other tank :-)
I got the answer I was looking for. Thanks again.
This thread can close :-)
Vidar
Thanks!
Ofcourse. The ground will not longer be the reference level. Because as the 2.nd tank fills up, so does the reference level.
Since the choise is to fill another tank, the 1.st tank really have 1/2 of the potential energy.
Say the tanks measure 1x1x1m. Center of mass is 0.5 meter above...
I'm not discussing or claiming free energy or over unity. I need help to debunk the claim made by my friends. Free energy does not exist. I know that already :-)
So, can you, or some other help me with some equations, or other explanations or examples I can use to disprove their claim? Because I...
I have a discussion going on with some friends. The discussion goes like this:
We have two identical tanks. One is empty. One is full of water. Both placed on the ground.
They are connected with a hose at the bottom. There is a ball valve in line with the hose.
The full tank has a given...
Since I discovered the homopolar motor, it has fascinated me a lot. Not because it has any practical use, but it works in spite of a non gradient magnetic field.
Normally, an electric motor works because the rotor is allways "chasing" a sticky magnetic spot. The magnetic gradient between weak...
Since the tomato isn't exactly elastic, but suffers from permanent deformation after impact, I guess that lots of the kinetic energy is released as heat, and will therefor not affect the scale in the same way as the superball is doing.
In addition, we're talking about G-forces which is very...