Recent content by lpettigrew

1. When two parallel wires carry current in the same direction, they exert equal and opposite attractive forces on each other. 2. ε=lvBsinθ ε=0.02*5*0.1*sin30 ε=0.005 V 3. Well, a conductor moving through a magnetic field has the potential to induce an emf, but this movement must be in such a...

If you think that you may be able to help me please feel free to reply to this thread or send me a private message ☺

Oh splendid thank you for your help 😁👍

Oh so the centripetal force is 0.034 N?

Oh yes, I can see your point, there are obscured areas where the physics is lost a little. No, I was just asking if the value I had calculated earlier for the centripetal force as 0.034 N was correct because I have seen it elsewhere given as 0.34 N instead and wondered whether I made a mistake...

Thank you for your reply. Right yes I agree with that. However, if I was intending to find the centripetal force specifically would my solution then be incorrect, as it corresponds to the acceleration?

But I have calculated the force not acceleration?Force and acceleration obey the vector laws - every question is not necessarily going to tell you that! Ok, right.

Thank you for your reply again. Right but where have these two equations come from in terms of the information given? Also, is my value for the centripetal force calculated earlier as 0.034 N incorrect? (which I thought may be out by a factor of 10).

Thank you very much for your concise response. So, g'=g+v^2/r g'=9.78+465^2/6.4*10^6 g'=9.8137..~9.81 ms^-2 However, where has the equation ##g' = g + a_c## come from?

Yes, I did mean that g is the value with a static Earth. I apologise but I am a little confused by your reply, although I appreciate it greatly. Where does my mistake lie? Is it that this is a very simple question wherein the value of g if the Earth were not spinning would simply be the measured...

If we think about the forces acting on an object at the surface of the Earth, these forces would be the weight force (mg) pulling downwards and the normal force (N) acting upwards . If the Earth were to stop rotating, then according to Newton's first law the forces must balance, meaning the net...

Thank you for your reply @PeroK I really appreciate it. 3. Haha. I think I was so taken by the theme of circular motion questioning that I neglected to see this was not applicable to the situation of a rocket. 😂 So, F=ma F=800*500 F=400,000 N (option c)

Question 1: I believe that the ratio would be b. 8:1 because by combining the formula for kinetic energy and momentum the expression Ek=p^2/2m can be obtained. Thus, for a body of mass 2kg with twice the momentum: Ek=2^2/2*2=1 For a body of mass 4kg with half the momentum: Ek=1^2/2*4=1/8...

@kuruman and @PeroK thank you for both of your replies. Ah, I see would my error be assuming that after separation they continue in different directions? So in actuality if they just separate then the momentums of skater 1 and 2 are both positive and this removes my misplaced negative sign...

Thank you for your reply. No, I had taken skater 1 and 2 to intially be traveling in the same direction together and then for skater 2 to be pushed by skater 1 and continue in this direction. I thought upon speration this would cause skater 1 to move in the opposite direction, would I be wrong?