Recent content by Lugytopo

Alright, thanks for the help.

Or would the force just be 600 + (61.2 * 2)= 722.4?

Well, let's see. We can change that equation to N= ma + mg. ma =(61.2*11.8)= 722.2 mg= (61.2*9.8)= 599.8 So N=1322 N--am I understanding this correctly?

Would the acceleration used in the F=M*A equation be a sum of the upward and downward accelerations?

Only the acceleration of the man changed.

I'm not 100% understanding what you are saying. The two forces are the elevator on the man and the Earth on the man. The mass is 61.2 Kg. A little bit more direction would be helpful.

I believe that the equation is F=M*A (I don't know how to use LaTeX yet). Do I have the force diagrams right? If the diagrams are not right I'm pretty sure that I will mess up everything.

There is a pre-drawn dot in the middle of the diagrams that represent the person. I also thought I showed the forces acting on the person--I only showed 2.

I know that there is the force of the Earth on the person and the elevator on the person with a net upwards acceleration of 2 m/s^2. If my force diagram is correct (which it may not be) the sum of the accelerations is 21.6. So would I take 21.6 * 61 kg to get 1321.9 N for the first graph?

Nevermind.

I guess the person actually weighs 600 N then?

I guess the person actually weighs 600 N then?

Sure, here is an updated version.

Right...Is the weight of the person 61.2 N or did I mess that up? I guess in that same lens is the force on the scale of the middle graph 600N?

For the first case, I guess it should be greater? So 600N*2m/s^2 which would equal 1200N? Is the force diagram correct for the first case?