Recent content by luv2learn

0.45n>0.25 log (0.45n>log (0.25) nlog(0.45)>log(0.25) n=log0.25/log0.45 n=1.736

Yeah, tx. I got the same thing but in a very long (and confusing) way. In the end n > 1.74 i.e. n = 2 Tx a lot. But is there a simple way of seeing if its a binomial distribution or not? I thought I know but clearly I don't. Or can the same answer be reached if I use binomial distribution...

(I'm really losing it, been at it for 10hrs.) Qn=0.45n ; Rejecting 1 is: Q1=0.451; Which implies accepting n-1, which is = 1-0.451 = 0.55 Q2=0.452; accept n-2 = 1-0.452 = 0.798; etc. So if x = minimum nr of articles to be submitted, then I'm actually trying to find Accept n-x = 1-0.45x...

Ok, so apparently I've got this whole question wrong, LOL So the probability that n artiles are rejected is Qn = 0.45 x n

Homework Statement The rejection rate of a certain journal is 45%. If the journal accepts articles at random, what is the minimum number of articles someone has to submit to have a probability of more than 0.75 of getting at least one article accepted? Homework Equations I'm almost sure...