Recent content by m00se

I know: \sum_{n=0}^\infty \frac{x^n}{n!}=e^x However, is there a similar solution for: \sum_{n=0}^\infty \left(\frac{x^n}{n!}\right)^2 Thanks in advance; I'm not very good at this kind of maths (I teach statistics :devil:), and I've been struggling with this one for a while.