Thank you for the replies, I am more than a bit confused now I use this ballistic calculator online http://www.convertalot.com/ballistic_trajectory_calculator.html
Entering a initial velocity of 12.5ms and a starting height of 120m and a angle of 90Deg straight up the resulting answer is...
I had V as the velocity after t as it is ascending I assume it would need to be a two part calculations. The first when the object is ascending and being slowed by gravity at 9.8ms till its final velocity is 0 hence the V = 0 at the beginning. Then a second calculations starting from a zero...
A helicopter is ascending vertically with a velocity of 12.5ms^-1. At a height of 120m above the ground a package is dropped out the door.
How long does it take for the package to reach the ground ?.
The attempt at a solution
I know
U = 12.5ms
A = -9.8ms
V = 0ms
S = 120m...
A toy car of mass 50g travels down a smooth incline at 30 degrees to the horizontal. Friction can be ignored.
Also Gravity is assumed to be 10ms
Calculate the net force on the car as it rolls down the slope:
For this I use M x G sin 30
so .05 x 10 sin 30 and got .25N - Hopefully...
Solved
How embarrassing, oerg you where spot on I forgot to take the square of the answer I think I have been working at this too long tonight :rolleyes:.
Thanks Again
Question is a golf ball is dropped from a height of 78m assuming gravity is 9.8 m s, What is the velocity of the ball after the first 10m.
I assume the equation to use is v^2=u^2+2ax
v = Final velocity
u = Initial Velocity
a = Acceleration
x = Displacement
So I plug in v^2 =...
Working with two moving targets ??
Hey guys, Here is the question I am working on
"A car traveling at a constant speed of 80kmh passes as stationary motorcycle policeman. The policeman sets off in pursuit, accelerating to 80kmh in 10 seconds and reaching a constant speed of 100kmh in another...