Calculating Final Velocity for a Dropped Golf Ball

[maca_404]

Question is a golf ball is dropped from a height of 78m assuming gravity is 9.8 m s, What is the velocity of the ball after the first 10m.

I assume the equation to use is $$v^2=u^2+2ax$$

v = Final velocity
u = Initial Velocity
a = Acceleration
x = Displacement

So I plug in $$v^2 = 0+2(9.8ms)(10.0)$$

Now according to the answer sheet V should be 14.0 m s but no matter how I plug this in I can't seem to get the right answer.

I think the problem is the way I am actually doing the math so if someone could perhaps step threw the maths so I can see where I went wrong.

Thanks for any help

 

[Oerg]

you shoudnt only learn about plugging values into the formula, you should learn the physical meaning of the formula! THAT IS VERY IMPORTANT I got 14 using the EXACT equation above, I believe you have made a careless mistake.

 

[HallsofIvy]

No, no one can possibly tell you what you did wrong, because you haven't told us what you did! The equation you have, v²= 2*9.8*10 is correct and gives v= 14 m/s. Apparently you made a mistake in the arithmetic, although it seems rather elementary to me! Since you didn't show what you did or tell us what answers you got, I can't tell if it was something as simple as forgetting to take the square root.

 

[maca_404]

Solved

How embarrassing, oerg you where spot on I forgot to take the square of the answer I think I have been working at this too long tonight .

Thanks Again