Recent content by Machinehead73

Would I take the what a kg = in lbs and divide it by that?

That would be 1 meter = 3.2808399 feet.

1 meter = 2.54 ft. right and 1kg = .0685 slugs right.

OK I need help with doing that an finding the uncertainty.

I see your point. I am sure the instructor is going by what is givin in the textbook. It gives an approximate value and a current best value. The approximate value is 6.67x10^-11 N*m^2/kg^2 the current best is 6.6742(10) x10^-11 N*m^2/kg^2. I think with this info he wants use to get our answer...

The gravitational constant I think that is being referred to is the one in my textbook and this 6.6742(10) x 10^-11 N*m^2/kg^2 . THe number in parentheses indicate one-standard-deciation experimental uncertainties in final digits, so the book says. And my problem says that to be aware the...

Homework Statement Does anyone know what the universal graviation constant is in english to 7 significant figures. metric is around 6.67x10^-11 and 1kg = .0685 slug. In the english system the constant is 3.43x10^-8 but I need to get it to the right sig figs. Can anyone help out on this. I...

So this means .5094(a) - .0153. Does this mean to multiply .5094 by the acceleration? Thanks

Thank you for responding! The excel give me y= .5094x - .0153 I am not clear on what the question is asking me then. What is the equation to find this out. Thanks

Homework Statement I have made a graph using excel the for a problem that I have. I used the best fit line function in excel to find my slope and y intercept. The question wants to know the force intercept of this. How can I find out what the force intercept is and an equation stating how I...

Absolute value of acceleration Help! Homework Statement I am getting a value of -1.94 m/s^2 for my acceleraton. An it wants to know the absolute value of acceleration what do I put down. It also state that the plus or minus is just to indicate direction. But the way the problems is computed...

Did you figure the coeffient of friction in. And What is the acceleration? I am confused on this on It does not ask for tension in the rope.

Ok I did a free body dieagram for both the masses. I found Fn, Ff, Fp anf the Net force of the system. I was told I was wrong. I that I go the direction wrong. I figured if the weight of the 24lbs mass on the 14 degree incline would put the mass of the 4 lbs mass. But I was told this is not the...

I still do not understand

Homework Statement There are two ramps back to back one with a 4 degree incline and the other with a 15 degree incline the mass on the 4 degree is 4 lbs and the other is 24 lbs the 4 lbs mass has a coeffient of .2 and the 24 lbs mass has a coeffient of .4 the two masses have a rope connecting...