Recent content by Machinist1

thank you Jay. i think i might have been getting mixed up with the catenary equation because it asks for weight per unit length. so i assumed it meant the full weight of the wire over 30ft span. not just the length of 1 foot of wire.

right sorry, forgot to mention the wire is steel with a weight of 491lbs/cuft. so .284lbs/cuin (.001542lbs per linear ft) and according to that website, the lowest point on the curve is .005". and i see on the chart i provided that the sag is .031" (lets say the chart is proven but uses a...

Hi all! I have an odd question that i thought somebody with a degree could help with. I am looking to find the formula to describe wire sag over a given length and given horizontal tension and given wire diameter. I believe the formula is a catenary but am unsure how to apply it to my...