Recent content by madeinusa

OK, how about this: sin(t) , t is time ω should be 1 so the frequeny f = ω/2π = 1/6.28 = 0.15923 Hz Is this correct?

according to this: Example: sin(x) This is the basic unchanged sine formula. A = 1, B = 1, C = 0 and D = 0 So amplitude is 1, period is 2π, there is no phase shift or vertical shift: https://www.mathsisfun.com/algebra/amplitude-period-frequency-phase-shift.html so if the period T is 2pi...

so for sin(x), ω = 1 then my calculation f = ω/2π = 1/6.28 = 0.15923 Hz should be correct?

Greetings, I'm confused about calculating frequency of sin(x) function. Applying basic equations I get this: T= 2pi f = 1/T = 1/(2pi) = 1/6.28 = 0.15923 Hz I know it's wrong, but what am I missing? Also, how can the period be in radians, I always thought that T should be in seconds.