Recent content by makeAwish

Means it is not like those support reactions? Like if we cannot rotate abt that point, the there is a moment; if we cannot translate vertically or horizontally, then there is a reaction vertically or horizontally?

No force?

If i push the book, there will be a frictional force, provided surface not smooth. Correct?

Ok, thanks! :)

Ok i think i get it. Thanks! :) Hmm, say i want to find it, :X is the direction of the reaction force at point O, perpendicularly to the slope (i.e into the post) or at an angle from the post?

So in this qns, when i analyse the post, i consider the forces acting on the post. If i add in the reaction force by grd on post, i will have another unknown, and i can't solve right? Means when i analyse the post, i shld consider my system as post and ground?

Yup. Think i understand the internal forces :) Thanks a lot! There are horizontal forces cos the beam can't translate horizontally at these points? (like the support reactions..) hmm.. is it?

hmm.. but i still can't solve that integration.. integrate sq rt[1+(2y)^2] with respect to y.

okay thanks. So at points P and O, is there a horizontal reaction force? Then for the two normal forces by beam on the each masses, are they considered as internal forces?

Hmm. Anyway, the reaction force by grd on post at point O should be pointing perpendicularly to the slope (i.e into the post) or at an angle to the slope?

Internal forces would be the normal forces? the reaction force by grd on post at point O is it an external force? We can apply the equations to each object as well? Hmm. How do we see if we should apply the equations to the block or apply by xy directions?

Homework Statement A uniform beam of mass mb and length supports blocks with masses m1 and m2 at two positions, as in Fig. P12.3. The beam rests on two knife edges. For what value of x will the beam be balanced at P such that the normal force at O is zero? Homework Equations sum of...

Actually for the integration of sq rt[1+(2y)^2] with respect to y, the integral limits are from 0 to 1. Sorry i realized i din mention the limits previously.

Okay. I tried and i get (say deter is x, for simplicity) \int cos^{2}x dx = \int (1/2)(cos 2x +1) dx = (1/2)[(1/2)sin 2x +x] But i can't find my intergation limits in terms of x. Cos initially it is from 0 to 1, at y=0, deter(which i call it x for simplicity) = 0 but at y=...

Homework Statement Blocks A and B weigh 400 and 200 kN, respectively. They rest on a 30degrees inclined plane and are attached to a post hinged at O by cords parallel to the plane, as shown in Fig. E06-1.3. The post is held perpendicular to the plane by force P. Assume that all surfaces are...