Recent content by mangren
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Finding a Cubic Polynomial with Remainders
This method looks easy but I don't get it. Please explain further. I tried again to solve it simultaneously resulting in 2cx + ax - 3a - 2b + 2d = 17x + 3, still far from the solution.- mangren
- Post #8
- Forum: Precalculus Mathematics Homework Help
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Finding a Cubic Polynomial with Remainders
just the basic stuff i know, but when all the x's come in, they confuse me... i tried to make P(x) = ax^3 + bx^2 + cx + d and divide it with x^2 - x + 2 giving a remainder x(b + c) -a(x + 2) - 2b + d which is equal to (5x + 4), and then divided P(x) with the x^2 + x - 1 giving a remainder...- mangren
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Finding a Cubic Polynomial with Remainders
Sorry, this is the first time I posted here. I'm lost in this problem. I tried starting solving it by using: P(x)/(x^2 - x + 2) = Q(x) + (5x + 4) and P(x)/(x^2 + x - 1) = R(x) + (12x - 1) but to no luck can't solve it... any suggestions?- mangren
- Post #3
- Forum: Precalculus Mathematics Homework Help
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M
Finding a Cubic Polynomial with Remainders
Homework Statement A cubic polynomial gives remainders (5x + 4) and (12x -1) when divided by x^2 - x + 2 and x^2 + x - 1 respectively. Find the polynomial. Homework Equations The Attempt at a Solution- mangren
- Thread
- Cubic Polynomial
- Replies: 7
- Forum: Precalculus Mathematics Homework Help