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Undergrad Quasi-Static Processes: Does dQ = 0?
I guess I am confused when dQ = 0. In Reif's Fundamentals of Statistical and Thermal Physics, in Section 2.9 on quasi-static processes, it states that the work dW done by the system when it remains in a particular state r is defined as dWr = -dEr. I understood this as saying that dW = -dE for...- manhattan_project
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- Forum: Thermodynamics
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Undergrad Quasi-Static Processes: Does dQ = 0?
We know that dQ = dE + dW for any system. However, in quasi-static processes, dW = -dE. Does this mean that dQ = 0 and no heat (Q) is absorbed or given off? If so, why is that?- manhattan_project
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- Quasi-static
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- Forum: Thermodynamics