Quasi-Static Processes: Does dQ = 0?

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Discussion Overview

The discussion revolves around the relationship between heat transfer (dQ), work done (dW), and changes in energy (dE) in quasi-static processes. Participants explore whether dQ can be zero in such processes and the implications of different types of quasi-static processes, such as isothermal processes.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Some participants assert that in quasi-static processes, the relationship dQ = dE + dW leads to the conclusion that dQ = 0 when dW = -dE.
  • Others challenge the assertion that dW = -dE applies universally to quasi-static processes, particularly questioning its validity in isothermal processes where dQ may not equal zero.
  • One participant references Reif's Fundamentals of Statistical and Thermal Physics, suggesting that the definition of work in quasi-static processes implies dW = -dE, but expresses confusion about when dQ equals zero.
  • Another participant agrees with the reference to Reif but argues that a system cannot remain in a particular thermodynamic state if its internal energy changes, suggesting that the equation may only hold for adiabatic changes.

Areas of Agreement / Disagreement

Participants do not reach consensus on whether dQ can be zero in quasi-static processes, with multiple competing views presented regarding the applicability of the equations and definitions involved.

Contextual Notes

There are unresolved assumptions regarding the definitions of quasi-static and isothermal processes, as well as the conditions under which dQ may equal zero. The discussion highlights the need for clarity on the thermodynamic states involved.

manhattan_project
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We know that dQ = dE + dW for any system. However, in quasi-static processes, dW = -dE. Does this mean that dQ = 0 and no heat (Q) is absorbed or given off? If so, why is that?
 
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manhattan_project said:
We know that dQ = dE + dW for any system.
However, in quasi-static processes, dW = -dE.
Who says that this is the case for a quasi-static process? What about an isothermal quasi-static process, where dQ is not equal to zero?
 
I guess I am confused when dQ = 0.
In Reif's Fundamentals of Statistical and Thermal Physics, in Section 2.9 on quasi-static processes, it states that the work dW done by the system when it remains in a particular state r is defined as dWr = -dEr. I understood this as saying that dW = -dE for quasi-static processes
 
manhattan_project said:
I guess I am confused when dQ = 0.
In Reif's Fundamentals of Statistical and Thermal Physics, in Section 2.9 on quasi-static processes, it states that the work dW done by the system when it remains in a particular state r is defined as dWr = -dEr. I understood this as saying that dW = -dE for quasi-static processes
I don’t have a copy of that book. But, it dorsn’t sound correct to say that a system remains in a particular thermodynamic state if its internal energy changes. The equation you have written is correct only for an adiabatic change.
 

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