My son's solution:
please comment, thank you.
We can only use 4 digits : 1,2,4,8 (2^0 , 2^1, 2^2, 2^3)
if we use 9 8's
8-8-8-8-8-8-8-8 and 2^n
2^27 . 2^n = 2^27
2^n = 1
8,8,8,8,8,8,8,8,8,1 only possible digits if true are 9 8's.
_8_8_8_8_8_8_8_8_8 = 10 spaces to...