Recent content by marchingt9

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    Why Does the Solution to My Differential Equation Include a +3?

    x' =-5x-y y' =4x-y I got x=ae^-3t+bte^-3t y=-2bte^-3t+2ae^-3t+be^-3t a=0 b=0 The answer is x=e^(-3t+3)-te^(-3+3) y=-e^(-3+t)+2te^(-3+3) I don't understand where the +3 comes from
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