Recent content by mariahkraft

hmm I bet I need to convert the mT to T huh?

for the cross product i got: (35vy+15.07)i+(35vx-11.07)j+(-9.54vx-6.97vy)k if I do this: (4.72E-17)=(35vy+15.07) and I solve for vy that is what the velocity in the x directions is? .431? Why am I solving for vy if i am looking for vx?

they are given in the problem b= (6.97i-9.54j+35.0k) and the vector force was not derives as is also given in the equation as: (vx)i+(vy)j+(1.58 km/s)k

Homework Statement A proton moves through a uniform magnetic field given by =(6.97-9.54+35.0) mT. At time t1, the proton has a velocity given by =vx+vy+(1.58 km/s) and the magnetic force on the proton is FB=(4.72 X 10-17N)+(3.45 X 10-17N). (a) At that instant, what is vx? (b) At that...

thank you!

A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE gives the radial distance (from the Earth's center) the projectile reaches if (a) its initial speed is 0.758 of the escape speed from Earth and (b) its initial kinetic...