1. The problem statement, all variables and given/known data A proton moves through a uniform magnetic field given by =(6.97-9.54+35.0) mT. At time t1, the proton has a velocity given by =vx+vy+(1.58 km/s) and the magnetic force on the proton is FB=(4.72 X 10-17N)+(3.45 X 10-17N). (a) At that instant, what is vx? (b) At that instant, what is vy? 2. Relevant equations F=qV x B 3. The attempt at a solution So, in order to find the velocity in the x direction I am assuming you do this: (4.27E-17)i +(3.45E-17)j=e[(vx+vy+1.58k)x(6.97i-9.54j+35k)] That is really all I have because I cant figure out the cross product. I end up with vx terms in the j direction and I don't know what to do with them. I hope I am making sense. Please let me know if youcan help. THANK YOU!!!