It came from the isolation:
1- x=V_ {xo} * t
2- y=V_ {yo}* t - \frac{1}{2} g t^2
In the second equation, I replace t by t=\frac{x}{V_ {xo}} and I replace V_ {xo} =V_ {yo}=Vsin45
I now have :
y=\frac{Vsin45}{Vsin45}*x - \frac{1}{2} g (\frac{x}{Vsin45})^2
And I isolate
y=x - \frac{1}{2} g...
Hi,
I need your help. Is my calculation correct?
1. Homework Statement
We have to build a launcher that will be able to reach a target that is place anywhere in a prism 3m X 3m X 1m. The launcher have to used a golf ball and gravity as source of energy.
I am trying to calculate what we need...