Recent content by Marty-0750

For a metric ruler held at arms length, 1 cm is close to 1 degree across the sky. Hold it out vertically and with one eye aligning the botton with 0 cm on horizon. Align star with edge of ruler. The cm reading is its approximate altitude +/- 1 degree For refinment due to somewhat varying...

Thanks, just what I wanted especially the 3rd link Marty

Yep. Marty

Hi All New here... Where can I get clear explanations of how s-process and r-process works in stars. Diagrams and examples how neutron capture bumps elements up the period table. Which elements are created by either process. Marty

Applogies. A slip of the finger on keyboard. This is meant to be a new topic - I'll repost. Marty

Declination of the Sun on the celestial sphere is 0 degrees at the March Equinox. If you are standing at the Tropic of Cancer you are 23.5 degrees north of the equator. The Sun will culminate (highest) at local noon at a zenith distance 23.5 degrees or an altitude above northern horizon at...

Where can I get clear explanations of how s-process and r-process works in stars. Diagrams and examples how neutron capture bumps elements up the period table. Which elements are created by either process. Marty