Recent content by Martyn59

Okay, I think I've almost got this M= change in height over change in time squared. No idea about intercept b though. I'll look it up. Thanks for your help. I appreciate it.

Thank you, yes, I've been thinking a bit more deeply about the whole thing, and I see that now. Thanks for your help.

Yes, darn it, when I wrote it out I forgot to square the time on the x axis. I've been giving this some thought I think I've figured out why the other formula doesn't work. (change in velocity over change in time) I was dropping a weight from 1900mm and getting 59 hundredths of a second and...

Hi if I understand it correctly, this is the process to find freefall acceleration of a falling body. S=ut+1/2at^2 Initial time and displacement is zero so, S=1/2at^2 find acceleration a=2(S/t^2) graph for change in displacement over time squared a= 2(yf-yi/xf-xi) (f=final i= initial) I...