- #1

Martyn59

- 4

- 1

S=ut+1/2at^2 Initial time and displacement is zero so,

S=1/2at^2 find acceleration

a=2(S/t^2)

graph for change in displacement over time squared

a= 2(yf-yi/xf-xi) (f=final i= initial)

I almost understand why that works,

But I thought that acceleration was found by change in velocity over change in time. a=v-u/t

But when I use this formula on the data from my experiments I get a wrong answer.any help would be appreciated.

Thank you.