Recent content by math007

thanks so much for the help man. I really appreciate it :-)

awesome thank you so much for the help :-)

e^x+1=e^2 e^x=e^2-1 lne^x=ln (e^2-1) x=ln (e^2-1)

raise e to get ln (1+e^x) e^(ln (1+e^x)) then e and ln can cancels? to get 1+e^x

to raise e to get y ln (e^y)=yln e=y

the exponential form of y?

ln (y)?

where can I read about the rules/ methods to solve ln /e equation because this is confusing me I don't know what to do. :'(

sorry I don't really understand.

Homework Statement I need to solve x: ln (1+e^-x)=-x+2Homework EquationsThe Attempt at a Solution ln (1+e^-x)=-x+2 x+ln (1+1/e^x)=2 x+ln (e^x/e^x+1/e^x)=2 x+ln ((e^x+1)/e^x)=2 x+ln (e^x+1)-ln(e^x)=2 x+ln (e^x+1)-x=2 ln (e^x+1)=2im stuck here. thank you