Recent content by MathHawk

This changes my bounds to 0 and 0. Can I stop here and claim that the answer is 0?

Oh my gosh, thank you. Made that way too hard on myself ;). I even thought about substituting using the 1-sin^2x inside the radical (instead of changing it to cos^2x) and it never occurred to me to look at the original question. Your help is very appreciated.

I've attempted solutions at this in two different manners and found myself stuck both ways. I'll show you the way that seems to make progress. The other way involves not factoring the junk under the radical in the denominator. Homework Statement \int^{1}_{0} \frac{3x^2 -1}{\sqrt{x-x^3}} dx...

You're right. However, I don't have that on paper (I have the + in place of the *). It's corrected on here when I use u substitution, and it doesn't affect my answer. Is there anything else, or did I just whoop a computer integral calculator (doubtful)?

You are on the Calculus forum, but in answer to your question acidic solutions have a pH of < 7.

I like to work these problems out and then check them with online integral calculators. Homework Statement \int^{\pi/4}_{0}tan2x * sec4x dx Homework Equations \frac{d}{dx}tanx = sec2x sec2x = 1 + tan2x The Attempt at a Solution This seems so simple, using the identities and u substitution...

Thank you, in other words.

You are my Bokonon, only you tell truths.

Because of circumstance (my desire to graduate in 5 years or less), I've been forced to attempt Calc 2 in 2 months time online over the summer. About 75% of it is going smoothly (compared with 105% or so of Calc 1). Homework Statement I'm to solve the indefinite integral: \int x *...