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Forums
mathlover1
Recent content by mathlover1
M
Discover the Sum of a Series: Find the Value with Expert Help
it seems so impossible to do!
mathlover1
Post #3
Jun 23, 2010
Forum:
Calculus and Beyond Homework Help
M
Discover the Sum of a Series: Find the Value with Expert Help
Find the value of sum 1+\frac{1}{2}-\frac{1}{3}-\frac{1}{4}+\frac{1}{5}+\frac{1}{6}-\frac{1}{7}-\frac{1}{8}+...
mathlover1
Thread
Jun 23, 2010
Series
Sum
Replies: 9
Forum:
Calculus and Beyond Homework Help
M
What is the Minimum Value of f(x) for Positive Real Numbers x and y?
That's why i am asking to you guys! This inequality is correct .. just need to be proven!
mathlover1
Post #5
Jun 22, 2010
Forum:
General Math
M
What is the Minimum Value of f(x) for Positive Real Numbers x and y?
I forgot to say that x,y are numbers such that x+y=1
mathlover1
Post #3
Jun 22, 2010
Forum:
General Math
M
What is the Minimum Value of f(x) for Positive Real Numbers x and y?
For all positive real numbers x,y prove that: \frac{1}{1+\sqrt{x}}+\frac{1}{1+\sqrt{y}} \geq \frac{2\sqrt{2}}{1+\sqrt{2}}
mathlover1
Thread
Jun 22, 2010
Numbers
Positive
Real numbers
Replies: 5
Forum:
General Math
M
Can you spot the mistake in this equation?
Well-done Njama, your answer is the correct one.
mathlover1
Post #7
Jun 14, 2010
Forum:
General Math
M
Can you spot the mistake in this equation?
yes it's -1 because (-1)^2=1 from the definition ;)
mathlover1
Post #4
Jun 14, 2010
Forum:
General Math
M
Can you spot the mistake in this equation?
Somebody find the mistake here: 1=\sqrt{1}=\sqrt{(-1)(-1)}=\sqrt{(-1)^2}=-1 \Rightarrow 1=-1
mathlover1
Thread
Jun 14, 2010
Mistake
Replies: 10
Forum:
General Math
Forums
mathlover1
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