Recent content by mathlover1
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Discover the Sum of a Series: Find the Value with Expert Help
it seems so impossible to do!- mathlover1
- Post #3
- Forum: Calculus and Beyond Homework Help
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Discover the Sum of a Series: Find the Value with Expert Help
Find the value of sum 1+\frac{1}{2}-\frac{1}{3}-\frac{1}{4}+\frac{1}{5}+\frac{1}{6}-\frac{1}{7}-\frac{1}{8}+...- mathlover1
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- Series Sum
- Replies: 9
- Forum: Calculus and Beyond Homework Help
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Graduate What is the Minimum Value of f(x) for Positive Real Numbers x and y?
That's why i am asking to you guys! This inequality is correct .. just need to be proven!- mathlover1
- Post #5
- Forum: General Math
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Graduate What is the Minimum Value of f(x) for Positive Real Numbers x and y?
I forgot to say that x,y are numbers such that x+y=1- mathlover1
- Post #3
- Forum: General Math
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Graduate What is the Minimum Value of f(x) for Positive Real Numbers x and y?
For all positive real numbers x,y prove that: \frac{1}{1+\sqrt{x}}+\frac{1}{1+\sqrt{y}} \geq \frac{2\sqrt{2}}{1+\sqrt{2}}- mathlover1
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- Numbers Positive Real numbers
- Replies: 5
- Forum: General Math
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High School Can you spot the mistake in this equation?
Well-done Njama, your answer is the correct one.- mathlover1
- Post #7
- Forum: General Math
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High School Can you spot the mistake in this equation?
yes it's -1 because (-1)^2=1 from the definition ;)- mathlover1
- Post #4
- Forum: General Math
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High School Can you spot the mistake in this equation?
Somebody find the mistake here: 1=\sqrt{1}=\sqrt{(-1)(-1)}=\sqrt{(-1)^2}=-1 \Rightarrow 1=-1- mathlover1
- Thread
- Mistake
- Replies: 10
- Forum: General Math