Recent content by mathman

the probability of drawing a particular real number = 0. You can't use uncountable sets (all reals between 0 and 1) to get probability.

As stated, assuming real space of n dimensions, the boundary consists of all points at a distance 1 from the origin. Your statement is confusing? What has f to do with the ball boundary?

Try Gptchat.

Mass is the main determinant, Look it up in wikipedia. https://en.wikipedia.org/wiki/Stellar_mass

Temp. too low - not a star. Very high temp. - fast burnout.

Spectrum may show up for longer living isotopes, which may be created in supernova events.

I used 'placed' instead of 'resting' and it works. My intent was y is a line segment with ends a and b while x is a line sub segment of y with ends c and d and ##c\ge a,d\le b##

Math qyuestion for AI (Skype) include an expression that x is resting on y (both straight line segments). AI insisted that x coincides with y, while my intent was only placing x on y. Does 'rest' have such a narrow definition?

As an aside: history should start with the observation that the milky way was not the entire universe. Other galaxies exist.

My question requires analytic geometry. AI (chatgpt or Bingchat) don;t have it.

Gave following to bing chat and chatgpt, Both gave wrong answers. Any thoughts? ------------------------------ Geometry problem: Semi-circle inside triangle: Triangle with known length sides a, b, c where a is the longest. Place inside the triangle a semi-circle with entire diameter resting...

Needs to be user defined.

Other than normal has to be user defined!

Gave following to chatGPT and got answer for ;inradius; of triangle, not radius of semicircle! Why? ==================================== Geometry problem: Semi-circle inside triangle: Triangle with known length sides a, b, c where a is the longest. Place inside the triangle a semi-circle...

My answers are ## r=\frac{b\times c}{b+c}sin(A)## and,## x=\frac{a\times c}{b+c},\ x## measured from angle B I get r as the distance from the diameter center to both other sides points of tangency. I use sine law to get rid of sin(B) and sin(C). AI radius is not radius of semicircle.