Recent content by mathmaniac1
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MHB Strings & Pulleys: Equilibrium, Find T1 & Explain
Please demonstrate how it would be like when the string is laid out in a straight line. Thanks Regards- mathmaniac1
- Post #7
- Forum: General Math
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MHB Is There a Formula for Summing 1/n Using the Digamma Function?
Looking for a pattern is not easy,how do you know when to stop looking and conclude there is no formula? I think most series including reciprocals have no formulae,but some have and is it possible to check?- mathmaniac1
- Post #11
- Forum: Calculus
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MHB Is There a Formula for Summing 1/n Using the Digamma Function?
Is it possible to figure out whether an inductive formula exists for sigma something?- mathmaniac1
- Post #9
- Forum: Calculus
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MHB Is There a Formula for Summing 1/n Using the Digamma Function?
Why not a formula f(n) such that f(n)-f(n-1)=1/n Why isn't it possible?- mathmaniac1
- Post #6
- Forum: Calculus
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MHB Strings & Pulleys: Equilibrium, Find T1 & Explain
T=6g and T1=6g+4g=10g But this is not the answer I had been taught,it is 2g. how can it be when some other forces like 4g and T1 are pulling T? Same question for m1. Things on the one side of the pulley have no effects on the other?- mathmaniac1
- Post #5
- Forum: General Math
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MHB Strings & Pulleys: Equilibrium, Find T1 & Explain
Modified it. My work? I can see nothing is moving,so I conclude 4g+6g=T1+T where g is acceleration due to gravity I don't see anyway to go further.- mathmaniac1
- Post #3
- Forum: General Math
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MHB Strings & Pulleys: Equilibrium, Find T1 & Explain
The system is in equlibrium,find T1 and explain. Thanks.- mathmaniac1
- Thread
- Pulley Strings
- Replies: 7
- Forum: General Math
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MHB Is There a Formula for Summing 1/n Using the Digamma Function?
sigma(1/n) Is there a formula for it?- mathmaniac1
- Thread
- Formula Summation
- Replies: 11
- Forum: Calculus
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MHB Throwing sandbags out of air balloon
An air balloon of mass M descending down with acceleration 'a'.A mass m is dropped out of it and the acceleration becomes a upwards.Find m in terms of M,a... The right answer is 2Ma/(g+a) The explanation I was given: The mass out of the balloon now has a+g acceleration. (How could it be when g...- mathmaniac1
- Thread
- Air Balloon
- Replies: 1
- Forum: General Math
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MHB Equations with rational degrees
Very very nice trick,impressive! using this,i can make any eq with only degree as 1/2 a polynomial no matter,how many terms there are... I'll be soon bringing another question about rational degrees(maybe) and I think the general question can also be solved by induction.Right? Let me see.- mathmaniac1
- Post #13
- Forum: General Math
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MHB Equations with rational degrees
No,I was thinking about A,B,C...representing polynomial functions on a variable (say x) but RHS a constant.There you can't do these kind of techniques when your purpose is to solve for x. But nice (funny?) answer,for my less informative post.- mathmaniac1
- Post #12
- Forum: General Math
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MHB Equations with rational degrees
I meant the modified 1 See my edit.- mathmaniac1
- Post #9
- Forum: General Math
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MHB Position time graphs for different acceleration
There is a Q,derive the eqns of motion using calculus and my txtbook derived x=x0+v0t+1/2at sqr and after all 3 eqns there is a note: These eqns can be used for non uniformly accelerated motion too. Now is my textbook wrong? I think by a he means f(t) for instantaneous acceleration at t. If...- mathmaniac1
- Post #21
- Forum: General Math
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MHB Position time graphs for different acceleration
no,my txtbook deroved the same equation taking a=dv/dt,integrating b/w the limits u and v gives the 1st eq of motion taking v=dx/dt and integrating and subbing v gives the 2 nd eq as x=ut+1/2at^2 but ther's a difference,a is instantaneous acceleration- mathmaniac1
- Post #18
- Forum: General Math
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MHB Position time graphs for different acceleration
but can't we just use the eq x=ut+1/2at sqr? with the value of a being given by f(t)? x=ut+1/2at^2 can be derived for non-uniform acceleration too- mathmaniac1
- Post #16
- Forum: General Math