Recent content by mathnap7

Apologies, I am not too familiar with using the LaTeX plugin. \frac{a^2b^3}{2(a^2-b^2)}\frac{(cos\phi -1)}{(a^2sin^2\phi +b^2cos^2\phi}

Hi All, I've been stuck on a problem and after much simplification, it has been reduced to the following: Is it possible to factor out the (a^2 - b^2) bit. For example, if a = b, the equation would not be valid. Is there any way to factor it out using manipulation? Best wishes, 'nap