omg you're a champion!
I totally didnt get the -W = 1 - 0.398 by using the T3 from part one
Now it just all fits together...it's great
Thankyou so much :-)
The answer in the book is 208.7 Deg C...but I got it using:-
\eta = 1-(T2/T1)
1 - (T2/T3) = 1 - (T3/T1)
1 - (800/T3) = 1 - (T3/290) - Figures converted to Kelvin
232000 = T3^{}2
T3 = 481.66K = 208.66 Deg C
I am having trouble with this question...It is from "applied thermodynamics for engineering technologists" by Eastop (Q5.2 if anyone has it)...
The Question:
Two reversible heat engines operate in series between a source at 527°C and a sink at 17°C. If the engines have equal efficiencies and...