Recent content by mcewendavid

omg you're a champion! I totally didnt get the -W = 1 - 0.398 by using the T3 from part one Now it just all fits together...it's great Thankyou so much :-)

The answer in the book is 208.7 Deg C...but I got it using:- \eta = 1-(T2/T1) 1 - (T2/T3) = 1 - (T3/T1) 1 - (800/T3) = 1 - (T3/290) - Figures converted to Kelvin 232000 = T3^{}2 T3 = 481.66K = 208.66 Deg C

I am having trouble with this question...It is from "applied thermodynamics for engineering technologists" by Eastop (Q5.2 if anyone has it)... The Question: Two reversible heat engines operate in series between a source at 527°C and a sink at 17°C. If the engines have equal efficiencies and...