Recent content by McKeavey

You may want to edit it :)

a) Hard to explain over this.. but First you need to break the velocity into x and y components. So.. Vy = 25m/sSin25 = 10.56m/s Vx = 25m/sCos25 = 22.65m/s K now so when you draw the projectile motion out, the ground is level all the way throughout the projectile motion. So maximum point of...

Which I do not know because I never learned it hah :/ I said I don't know anything about momentum :/

Homework Statement A neutron with velocity 5E5 m/s and a mass of 1.66E-27 collides with a helium nucleus, mass of 4(1.66E-27) with a velocity of 3.7E5 m/s as shown. If the speed of the neutron after collision is 5E5 m/s and it is moving in the direction of motion of the nucleus after collision...

Hmm I got angle as 25.24. And then the resulting coefficient of friction as 0.59 :S By the way thanks for the other thread, I got the right answer for it ^^ Now..To finish this.. :(

Homework Statement If a curve with a radius of 60m is properly banked for a car traveling at 60km/h (16.66m/s) with no friction, what must be the coefficient of friction if the car is not to skid when traveling at 90km/h (25m/s) Homework Equations mac = mv^2/r The Attempt at a...

Homework Statement A coin is placed 18cm from the axis of a rotating turntable of variable speeds. If the coefficient of friction is 0.68, what is the maximum r.p.m that the coin can handle before sliding off? Homework Equations This is basically what I need.. I know there's mv^2/r But...

I need another equation to sub in for the v eq :/

Vheli = (a)heli(30s)?

V1y = 2at² - dy/t d = ½(a)t² ?

Um d = v1 + (.5)at^2 V1² =v2²-2ad? :S

Ohh.. Hm. V2heli = V1flare? what equations do i use :S

Nono the equation is only for finding out the height of when the flair was released.

Well ill try to shorten it because i need the answer asap. y = 0 + 0.5(9.8mls^2)(10s)^2 = 490m but that's wrong

Im on my phone its hard to type out my three pages worth of notes lmao