Recent content by Medd
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Freefall in a Newtonian gravitational field
Many thanks ! Okay ! Thank you very much for all the help ! :biggrin: I hope I'm not getting too off topic here but, since in most cases you can't even solve the equation (this is news for me, I'm shocked), what would an engineer do to predict complicated motion described by complicated...- Medd
- Post #11
- Forum: Introductory Physics Homework Help
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Freefall in a Newtonian gravitational field
Equation So I finally came up with this, pfew :smile: : t = \frac{\sqrt{h^{3}}(arccos\sqrt{\frac{y}{h}} + \sqrt{\frac{y}{h} - \frac{y^{2}}{h^{2}}} ) }{\sqrt{2k}} This is good but isn't the whole point of studying motion to be able to write the position as a function of time ?- Medd
- Post #8
- Forum: Introductory Physics Homework Help
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Freefall in a Newtonian gravitational field
Oops ! My bad. Thanks for spotting that ! So that gives us : ∫ \frac{dy}{\sqrt{\frac{1}{y} - \frac{1}{h}}} = - \sqrt{2k} * (t + C') And I have the LHS integration problem again.- Medd
- Post #5
- Forum: Introductory Physics Homework Help
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Freefall in a Newtonian gravitational field
Integration difficulties Hi ! Thanks to your hint, I was able to make some good progress towards the solution of my differential equation. If we assume an initial height "h" (y(0) = h) , and a initial speed of zero (v = dy/dt (0) = 0), we can start solving it : \frac{d^{2}y}{dt^{2}} =...- Medd
- Post #3
- Forum: Introductory Physics Homework Help
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Freefall in a Newtonian gravitational field
1) The problem statement : For this problem, We use Newtonian Mechanics. We are placed in a geocentric frame of reference. An object (of which the mass is irrelevant for this problem) is released into the Earth's gravitational field at an altitude p(0) with no velocity whatsoever. The...- Medd
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- Field Freefall Gravitational Gravitational field Newtonian
- Replies: 11
- Forum: Introductory Physics Homework Help