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Finding Taylor Polynomial of Degree 4 for f(x)=sqrt(x) About a=4
I need to find the Taylor polynomial of degree 4 expanded about a=4 for the function f(x)=squareroot of (x)=x^(1/2) This is what I've started with but I'm not sure how to proceed and if I even started correctly: f'(x)(-1/2)x^(-1/2)=1/2sqrt(x) f"(x)=(-1/4)x^(-3/2)=-1/4x^3/2...- meganlz09
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- Polynomial Taylor
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- Forum: Calculus and Beyond Homework Help