Recent content by meguco0314

Yes thank you so much! Your help was awesome! I learned more than a thing or two from this, and I hope others will benefit from this thread as well. :)

Yeah that makes a lot of sense! The direction of the current must be from A to B then.

See my edit, I got a bit exited and thought a bit wrong but corrected myself. Hmm, the direction I am not sure. I think it goes from A to B but I am not sure. How would I know that?

2 A must flow through R1. And if there is 6V across R3, 1,5 A must flow through. But since the total current should be 3 A, 0,5 A must go through the AB connection. Correct? Edit: "But since the total current should be 3 A" I got that wrong I believe in this context. But everything adds up! 2A...

The voltage is the same for each branch when parallel. But, sorry, I don't know how to go forward from this. The connection between the two branches makes this very complicated for me. The voltage for R1, R2 combination are 6V. How do I calculate the voltage for R1 and R2 separately? I need...

Yes I believe so. The difference in current between R1 and R3 should be the current that goes through A and B. I'm not quite sure about the voltage of R1 and R3 though. If I understand correctly R1 has 4V and R2 has 2V? R3 3V and R4 3V. If this is correct then R1 has the current 4/3 A and...

We have U=R*I and across the R1 , R2 combination we have, as you said, 3 A passing through 2 Ω. The voltage should be 3*2 = 6V in both combinations since the combinations have equal resistance. Can I figure out the voltage for each resistance now with this information?

Both the R1 , R2 combination and the R3 , R4 combination has 12V, correct? If so, then according to Qwertywerty I can use the ratio between R1 and R2 and then use that same ratio with the voltage. So we have a ratio of 2:1. If my theory is correct, the voltage of R1 should be 4 and R2 should...

As you said there are a connection between the two branches. I wasn't sure if R1 and R3 were in series or not because of this, but now I understand. When I do 1/R = 1/R1 + 1/R2 I get that the resistance is 2 Ohm. The resistance for R3 and R4 is 2 Ohm also. Total resistance for the whole...

How do I determine the current in either? Can I use that 1/R = 1/R1 + 1/R2 Do you refer to this: 1/R = 1/(R_1+R_3) + 1/(R_2+R_4) Is this wrong?

Homework Statement [/B] What is the current between points A and B? The current I is unknown. The voltage is 12V. R1 = 3 Ohm R2 = 6 Ohm R3 = R4 = 4 Ohm Homework Equations U= R*I The Attempt at a Solution Total resistance from both branches: 1/R = 1/(R_1+R_3) + 1/(R_2+R_4) 1/R = 1/7 +...