Recent content by mejo.gejo

trust me, you can get nothing better from altering initial situation. there is some obvious explanation, but my brain is tilted right know and is of no use. i am looking for someone who know explain to me galvanometer in terms of electric field , something like this...

well, the whole point is to make readings without making any changes in circuit( that's the reason for big galvanometer resistance) so, that's not my answer. thx on reply.

i have problem to conceptualize this old galvanometer readings for voltage drop. i plot a diagram of circuit of interest for bether explanation of what's bothering me. so, in DC circuit with some resistor in series, electric current is constant and is of some known value. and if i want to use...

it will flow even if there is no net force (electric field). you can understand this if you address for concept of force on right place, Newton's laws- first one says that it is posible to have motion (uniformly rectilinearly) with zero net force. in electric that means if there is no resistance...