Recent content by melby2188
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Systems of equation w/3 stock solutions
ok thanks this is what I am getting using x+y=250 and .05x+.28y=.17(250) x=119.565 and y=130.435 putting this back into the cost function 1/1000(28x+38y) i get $8.30 does this sound right?- melby2188
- Post #5
- Forum: Calculus and Beyond Homework Help
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Systems of equation w/3 stock solutions
Sorry,This is what i have so far: x+y+z=250 and .05x+.28y+.40z=.17(250) and i think the cost function should be something like c(x,y,z)=1/1000(28x+38y+50z) I know i need to use systems of equations I am just not sure how to solve it with the cost equation or if the cost equation is correct.- melby2188
- Post #3
- Forum: Calculus and Beyond Homework Help
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Systems of equation w/3 stock solutions
one must create 250ml of a 17% salt solution. You have three stock solutions. One liter container of a 5% salt, a 500ml of a 28% salt solution and a 400ml of 40% salt solution. Calculate the cheapest method of preparing the 17% salt sol. if the 5% salt solution costs $28 per liter, the 28%...- melby2188
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- Replies: 5
- Forum: Calculus and Beyond Homework Help