Recent content by Melika

The original post i guess. I'm working on the same problem. The time it takes to reach X% of its terminal velocity is t=(-m/b) ln((100-x)/(100)). Vy=(mg/b)(e^(-bt/m)-1) If i plug in t to this equation i get Vy=(mg/b)(e^(ln((100-x)/(100)) -1) But I'm not sure what to do next? i know i need to...

how would you go from t=(-m/b) ln((100-x)/(100)) to the vertical displacement?