Recent content by Melina

I got 46.8 degrees from using the initial horizontal velocity: 15m/s and the vertical velocity: 16m/s. Theta = tan^-1 (16/15) Theta = 46.8 degrees

Speed is distance over time. I calculated that the distance traveled by the ball is (22sin (2*46.8))/ 9.81 = 49.24 meters So after one second that the ball was kicked, speed = 49.24m / 1 second = 49.24 m/s This is still incorrect

Homework Statement A soccer ball is kicked with an initial horizontal velocity of 15m/s and an initial velocity of 16m/s. What's the speed of the ball 1 second after it was kicked? Homework Equations Initial velocity = sqrt([horiz. Velocity]^2 + [vertical Velocity]^2) Final velocity = initial...

Homework Statement The half thin steel plate has a radius of 4 meters and a surface density of (3+r) kg/m^2, where r is the radial distance from the origin. Using calculus, find: A. its area B. its mass C. Its center of mass with respect to the origin shown, D. It's rotational inertia about the...