Recent content by ment4ll

Thats what I didn't know now I see that A=L^3, B=L^3t and C=L^3/t^4 I didn't know that you had to cancel out to get the dimension and I didn't know that V=L^3 V=L^3 because the formula for volume=lwh and those are 3 lengths multiplied together.. is that right?

wait, would the deminsions of A, B, and C all be L3?

Well I am assuming that C is Length while A is electric current and B is mass .. I'm trying to comprehend it man, but that is just guessing based on what you've explained :\

Okay, the unit is m/s and the dimensions is L/T, now I understand that.

Sorry guy, I'm just not grasping it at this point .. wouldn't the dimensions of A+B = X then? I'm confused about where the M3 comes from ..

Another thread on the forum said the answer is L^3/T^4 but I have no idea how to conclude that https://www.physicsforums.com/showthread.php?t=251970

So C has to be something measurable to volume right?

I mean, yea I get that A, B/t and Ct^4 all are combined units of volume, they have to be. I don't understand how you get the units of C if it isn't the answer I posted. Sorry if I'm noob at this, I've never taken a physics class in my life (besides this one).

Homework Statement The volume of an object is given as a function of time by V= A + B/t + Ct^4 Find the dimension of the constant C. Homework Equations N/A The Attempt at a Solution I don't understand dimensional analysis completely .. I understand it on simpler terms, but in...