Recent content by mgoff87
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Undergrad Component form of magnetic field
I figured it out...all i needed to do was set it up as a matrix and find the determinate(ie the cross product) and everything worked out fine!- mgoff87
- Post #3
- Forum: Electromagnetism
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Undergrad Magnetic field in a particle accelerator
got it! Alright, the only thing that was confusing me was the units for momentum and trying to set as one variable... What i found was B = mv/rq where mv was the momentum that they gave us. After that it was just plugging in the numbers. I got my final answer to be 1.5 T- mgoff87
- Post #4
- Forum: Electromagnetism
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Undergrad Component form of magnetic field
A 2.0 m long wire carries a current of 8.2 A and is immersed within a uniform magnetic field B. When this wire lies along the +x axis, a magnetic force F= (-2.2 j)N acts on the wire, and when it lies on the +y axis, the force is F = (2.2 i -4.2k)N. I saw through inspection that B in the y...- mgoff87
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- Component Component form Field Form Magnetic Magnetic field
- Replies: 2
- Forum: Electromagnetism
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Undergrad Magnetic field in a particle accelerator
Protons with momentum 2.2×10−16 kg*m/s are magnetically steered clockwise in a circular path 1.8 km in diameter at Fermi National Accelerator Laboratory in Illinois. I am asked to find the magnitude and direction of the field in the magnets surrounding the beam pipe... I'm fairly certain...- mgoff87
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- Accelerator Field Magnetic Magnetic field Particle Particle accelerator
- Replies: 3
- Forum: Electromagnetism