Recent content by middleearthss

Homework Statement Derive the Hamiltonian equation in terms of momentum and position ( p and r) for the given system whose lagrangian is stated as L=ř^2/(2w) - wr^2/2 Homework Equations L=ř^2/(2w) - wr^2/2 and H=př-L The Attempt at a Solution Notice here ř means first derivative of r. As i...

Thank you both for clear guidance, i am very much grateful.

I see it 50 - 2t = 3t - 25 t = 15 and we used 2m1a1 = m2a2 because their accelerations are in basically the same as they cannot move away from each other. So m1a1=m1a2 from above. That was it right?

It cannot. Ohh now that means if i take A to be accelerating in the - direction and B to be accelerating in the + direction the accelerations depend on each other and are lessened. acc of the box 1 equals its original acceleration without the influence of box 2 - the acc of the box 2 and so for...

No, the acceleration of either box depends on the mass of the other. The heavier its partner the lower its acceleration.

From Newtons second law ma=F the a1= (T-F1)/m1 and a2= (F2-T)/2m1. Thats the only connection i see, is there more?

Thats the solution! 15 sec. I respect that you can't give me the work and I am hoping you will be patient as i work my way through. Now, my main problem is setting everything up. In the free body interpretation i can formulate that if i choose right side as increasing of x and call m1 pulling to...

Ok, what would be you answers, what is the t at which string breaks and what was your calculation.

I do understand that directions should be taken into account but i cannot formulate the equation that allows me to solve for t. From the equations above it did occur to me that T1=T2 but how do you place everything into a form of an equation. What is a in this formula. I have F's and masses but...

So T1=m1a1 - F1(t) and T2=m2a2 - F2(t) so total tension is T1 + T2? What would in this case be a? Only thing i have are the forces and masses?

I don't know how to do that and it all seems confusing, i can't find a role for masses anywhere.

Good point, it seems as if when c equals 0 only box B pulls to the right. So the tension in that case would not be 0 which would be the case if no box is connected to the left but still some value as box A resists movement. What comes to my mind is that the acceleration of the two boxes in the...

Homework Statement A string is connected to a box A mass M at its left end and a box B mass 2M at its right end. Boxes A and B start pulling in opposite directions at the same time with forces which are time dependent and described by functions F(t)=Ct for box A and F(t)=Dt for box B. Values of...

Oh sorry did not know the routine,...

Hi, i just signed up and am new to all this. First time in a forum also. Main reason i signed up is so can help others, chat physics with rest and also to get some help on some main issues I am experiencing along my study. No homework or similar but things i get stuck at. To introduce myself a...