Recent content by Mihai_B

@PeterDonis : I concur. Also using multiple collisions with what remains from previous collisions (maybe 3BP- 3body problems or why not - 5 or more - colliding BH) - aka complicated collisions between multiple spinning BH (anyways, all BHs actually do have some spin, but we approximate this in...

It is instead possible if we have 2 colliding black holes to get energy out of the collision in the form of GW. It's possible that what is left of your "probe" (or at least parts of it) could have been converted into gravitational waves during the collision...

It's a bit more complicated but if you are interested in such a theory you could try and read (or get) this book The Meaning of Relativity, the 6th edition (you must get the 6th edition if you want Einstein's latest or rather last revision - published in december 1955 a less than a year before...

"A complete field theory knows fields and not the concepts of particle and motion. For these must not exist independently of the field but are to be treated as part of it." July 1935, A.Einstein, N.Rosen - The Particle Problem in the General Theory of Relativity If we consider particles like...

B is actually called magnetic inductance and I think it's for a good reason. The electric field at some position will vary with charge variation like this : dE = dq r / (4πε r3) , with "bold" r as position vector. And the force acting on another particle is written as F = q E = q1 q2 r / (4πε...

About that ... Note to the Fifteenth Edition In this edition I have added, as a fifth appendix, a presentation of my views on the problem of space in general and the gradual modifications of our ideas on space resulting from the influence of the relativistic view-point. I wished to show that...

"Where would the energy go (hypothetical) ?" I know there are people with far better math apparatus than mine - I will let others complete me or give answers in other perspective - , but since I like very much to study Einstein-Rosen bridges I can recommend you a brilliant study article (also...

Hi and thanks for the reply! - I wrote Pα but i really actually used Pα = " Pα/dτ " . Sorry. - You are correct - I got the sign wrong for P0. It's -mc/a - d(mc/a)/dτ, d(mvx/a)/dτ, etc, which is what I ment to write (my original notes are correct), sorry my transcription got a little wrong...

Can anyone help me find any mistake in this expansion ? (I've asked it also in other places but I got no answer)) Pα= e Fαβ Uβ c = speed of light m = "rest" mass e = charge a = sqr(1 - v2/c2) v2 = vx2 + vy2 + vz2 dτ = dt a (proper time) momentum 4 vector : Pα = [mc/a , mvx/a , mvy/a ...