Mike_bb's latest activity

Space-time curvature.

This can only represent "gravitational fields" on the chosen background. It can't, for example, represent a black hole spacetime...

This has several excellent answers and I cannot improve on them. I just have this persistent nagging voice wanting to express this...

Very similar to post #6. $$ a^0=a^{x-x}=\frac{a^x}{a^x}=1 $$

And once there is some actual evidence supporting your preference then it will be an acceptable topic for PF. But even then it would be...

Why are you so sure?

We are already in that situation with GR alone. So why should we hypothesize about unknown possible future theories when we can already...

Exponents are about multiplication, and 1 is the multiplicative identity. If exponents represented repeated addition the zeroeth power...

I won’t argue against that. In either case, the local gravitational force, like fictitious forces, is not measurable either way. It can...

Another way to look at it ##a^0 = 1## ##a * a^0 = a * 1## ##a^1 = a## Of course you can reverse the steps and conclude that ##a^0...

##a^0=a^1a^{-1}=a\frac{1}{a}=1##

Well if your ##x## is zero, then you will have no ##a##'s, so just the ##1## in the begining.

Or, more generally, ##a^{n+m}=a^na^m## implies ##a^0=1##, because otherwise ##a^{n+0}\neq a^n##.

It's consistent with ##a^{n+1}=a\cdot a^n##

Hello! I have problem in understanding why ##a^0=1##. I represent ##a^x## as ##1*a*a*a*a*...*a## (x times) Why ##a^0=1##? Why is...