Mike_bb's latest activity
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MMike_bb replied to the thread Undergrad Why ##a^0=1##?.Could you explain how does it work? How is it possible to combine an empty product with original factors (see below)? Thanks. "The...
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MIn arithmetic, ##x^k## is defined recursively. The recursive step is ##x^k=x^{k-1}x##. What is the base case then, ##x^0##? For the...
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M$$a^x:=\exp(x\ln a),\quad \exp(x):=1+\sum_{k=1}^\infty\frac{x^k}{k!},\quad a>0$$
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M##a^0## can't be ##0## because if ##a^0=a\cdot 0 =0## for every ##a##, then ##0^0=0##, that is not true in mathematics ... In addiction...
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MMike_bb reacted to martinbn's post in the thread Undergrad Why is gravity a fictitious force? with
Agree.
Space-time curvature. -
MMike_bb reacted to PeterDonis's post in the thread Undergrad Why is gravity a fictitious force? with
Agree.
This can only represent "gravitational fields" on the chosen background. It can't, for example, represent a black hole spacetime... -
MThis has several excellent answers and I cannot improve on them. I just have this persistent nagging voice wanting to express this...
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MVery similar to post #6. $$ a^0=a^{x-x}=\frac{a^x}{a^x}=1 $$
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MMike_bb reacted to Dale's post in the thread Undergrad Why is gravity a fictitious force? with
Agree.
And once there is some actual evidence supporting your preference then it will be an acceptable topic for PF. But even then it would be... -
MMike_bb replied to the thread Undergrad Why is gravity a fictitious force?.Why are you so sure?
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MMike_bb reacted to Dale's post in the thread Undergrad Why is gravity a fictitious force? with
Agree.
We are already in that situation with GR alone. So why should we hypothesize about unknown possible future theories when we can already... -
MExponents are about multiplication, and 1 is the multiplicative identity. If exponents represented repeated addition the zeroeth power...
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MMike_bb reacted to Dale's post in the thread Undergrad Why is gravity a fictitious force? with
Agree.
I won’t argue against that. In either case, the local gravitational force, like fictitious forces, is not measurable either way. It can... -
MAnother way to look at it ##a^0 = 1## ##a * a^0 = a * 1## ##a^1 = a## Of course you can reverse the steps and conclude that ##a^0...
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M##a^0=a^1a^{-1}=a\frac{1}{a}=1##