Mike_bb's latest activity

This statement suggest you still do not grasp the relativity of simultaneity. Consider for space like separated events ##A,B##, I can...

Proper time recorded by some particular observer's clock at some particular event is independent of any choice of reference frame. But...

Time doesn't depend on frames. Only time interval depends on the frames. (as in example above)

[clock A = 80s] and [clock B = 100s] -> [clock A = 100s] and [clock B = 80s]. clock a=80s -> clock a=100s - it's correct. But how is it...

Case 1) Reference frame: A E1: clock A shows 100s E2: clock B shows 80s Case 2) Reference frame: B E3: clock B shows 100s E4: clock A...

They can. A clock can (and shall) for example show at 2 P.M. another time than it showed at 1 P.M.

That's not happening at the same moment. With reference to Observer B's rest-frame: Clock B first shows 80s (E2) and ##20s## later...

Big thanks!! This solved my problem! But is your last edited version correct? I mean "Clock A shows then ##100s/\gamma=80s##." and...

That can never happen. You have misunderstood something. That can never happen, either. A reading on a clock, like any measurement, is...

Let we have 2 events. In the 1st IRF these events happen simultaneity, but in the 2nd moving IRF these events happen at the different time.

Dale, I've read about the relativity of simultaneity but I can't understand how does it apply to example with observers.

Clock A reads 100 and clock B reads 80 at the same moment in frame A. Clock B reads 100 and clock A reads 80 at the same moment in frame...

@Mike_bb are you familiar with the Lorentz transform equations?

Yes. But I used them several times.

Do you want to say that if I see in the frame A to frame B(to clock B) and if observer from the frame B see in the frame A(to clock A)...